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I am trying to get a python code to run on boot on the raspberry pi. I added the following line to the .bashrc file at the end of the file:

sudo python3 /home/pi/code.py

The pi uses python2 to run the code instead of python3. Why is this happening and how can I make it run python3?

Thanks

  • Does this answer your question? Python 3 default python – M. Rostami Jan 24 at 19:45
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    No, I don't want to make python3 my default python version. Thanks though. – user113912 Jan 24 at 20:09
  • What is the added line to .bashrc meant to do? Call the script at shell start? How do you know it is not working? – joan Jan 24 at 21:02
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    Please show the first line of code.py – bls Jan 24 at 23:46
  • .bashrc will not be executed at boot, so whatever is starting your script at boot time using Python2 it is not the line you're looking at. – Dmitry Grigoryev Jan 27 at 12:21
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.bashrc is NOT intended to run scripts.

It is run each time a non-login interactive shell is started and is used to configure the shell.
~/.bashrc: executed by bash(1) for non-login shells.

There are many ways of running scripts, depending on what you are trying to do. See https://raspberrypi.stackexchange.com/a/47537/8697 for an example.

(There are other problems with the script, but as you shouldn't use it for this purpose, not relevant.)

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