I have used the code from github and in that code i am implementing the raspberry pi and the RFID and relay module with magnetic door unlock. Everything is working Okay , the RFID , the Relay module and the button. When the Card is scanned the relay module light turn on and i can hear the tick sound of the relay as well (with no current being passed in the 12 V Magnetic Door ) and the Button as well , when i click to unlock via button it works perfectly as well without the Magnetic Door. The issue comes when 12 V power is passed to the Magnetic module, in this case the RFID scans the card for the first time and the relay light is on and the module is working correctly but as soon as the relay module goes off the RFID card stops working. But the Button keeps working. I can unlock via button many times but the RFID cards works only for the first time and again to make it work i have to restart the Raspberry. I have checked the whole code and the whole connection and everything is right , everything is working perfectly until 12 V current is passed in the relay. Just for the information , i have ordered different relays and tested with them as well but still same.
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Ah let me see. Let us make things as simple as possible, but not simpler. So your RFID function works only for the first time, then you need to reset Rpi. I remember when I tested my RFID module, I wrote 3 functions: (1) A function to read RFID card, (2) Another function to print what is read from the RFID card. (3) A main function to loop the first two functions. If you write a minimal program to just test the above three functions, then it should be much easier to debug. You might search my RFID demos in the following forums: (a) SO, (b) EE SE, (c) Rpi SE.– tlfong01Commented Apr 24, 2021 at 7:36
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1The RFID works all okay until i power up the 12 V Electromagnetic Lock. The Relay is working Okay as well until the 12 V Lock is not given the power. It scans the RFID and then the light on relay turn on and i can hear the tick of relay. It works perfectly but as soon as the Electromagnetic Door is powered on the RFID works for the first time and then it kinda stop working but the button to unlock works like a charm.– Ahtisham AshrafCommented Apr 24, 2021 at 10:14
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1I have implemented it exactly like mentioned in the code github.com/lesp/LXF230-RFID-Door-Lock , the issue that the RFID works as well and it works as many times as we want until the 12 V power is supplied to the relay. As soon as power is turned on the RFID stops working. If i turn off the power now it still doesn't work until the raspberry is restarted– Ahtisham AshrafCommented Apr 25, 2021 at 11:11
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1now let me explain in bit detail 1. Turn on the Raspberry with the python code. 2. Scan the RFID Card, it is working perfectly with no limit to scan, i can scan it 1000 times without any issue. Relay light is on and relay is tripping 3. Press the button to unlock working Perfectly. Relay is on and relay is tripping. Now Let's turn on the 12 V Electromagnetic Door Power 4. RFID Scans the card, Relay light is on , Relay is tripped. Relay is closed again , light in relay goes off. Now i when scanning the card it is not working again. 5. Button unlock works all the time– Ahtisham AshrafCommented Apr 25, 2021 at 11:11
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1There is an issue between the relay and the reverse voltage i guess that relay passes to the board which disable the RFID as per me but i am not sure. The code is not having any issue until i turn on the 12 V power to relay– Ahtisham AshrafCommented Apr 25, 2021 at 11:18
5 Answers
I have seen exactly this problem on a very similar application. Instead of a solenoid it was a common magnetic relay that was being activated to control mains power to a piece of equipment.
I finally found that the problem was a subtle incompatibility between the RFID library and the connections of the Pi to the RFID module. It turned out that the code was not actively driving the reset pin to the module. But, you said you've check both of these and you are sure they are correct so that can't be it.
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Elliot Alderson, Ah, many thanks for your very important and useful tip on "subtle incompatibility between the RFID library and the connections of the Pi to the RFID module.". So perhaps me and the OP should go back and look into the RFID Library again. Cheers.– tlfong01Commented Apr 29, 2021 at 8:06
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@Ahtisham Ashraf, I only read this new answer just now. So we need to go back to square 1! :)– tlfong01Commented Apr 29, 2021 at 8:10
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1@tlfong01 Yes i will debug the code and will check some other libraries as well. I will update here real soon. Commented Apr 29, 2021 at 12:03
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1Yes i am debugging it further , If you have the code for RFID Solenoid Lock , can you send me it here and i will compare how it is working and what i am lacking in this code. @tlfong01 Commented May 1, 2021 at 5:34
Thanks a lot guys for the Help, It took a long time to debug , there were issues in the Python Script and the SPI cables, as soon as the RFID is scanned it sends signal to one SPI terminal and on the same terminal another response was sent as well causing the RFID to freeze and unable to proceed.
#!/usr/bin/env python3
from evdev import InputDevice
from select import select
import RPi.GPIO as GPIO
import time
from gpiozero import Button, OutputDevice
release = Button(27)
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(13,GPIO.OUT)
GPIO.output(13,GPIO.LOW)
rfid_presented = ""
keys = "X^1234567890XXXXqwertzuiopXXXXasdfghjklXXXXXyxcvbnmXXXXXXXXXXXXXXXXXXXXXXX"
dev = InputDevice('/dev/input/event0')
def button_open():
GPIO.output(13,GPIO.HIGH)
print("DOOR OPEN")
time.sleep(5)
GPIO.output(13,GPIO.LOW)
print("DOOR LOCKED")
while True:
release.when_pressed = button_open
time.sleep(0.1)
r,w,x = select([dev], [], [])
for event in dev.read():
if event.type==1 and event.value==1:
if event.code==28:
if rfid_presented=="1649137959" or rfid_presented=="1664741015":
# Unlock Door
print("Unlocking Door.")
GPIO.output(13,GPIO.HIGH)
time.sleep(5)
# Lock Door again
print("Locking Door Again.")
GPIO.output(13,GPIO.LOW)
else:
print("Access Denied.")
rfid_presented = ""
else:
rfid_presented += keys[ event.code ]
I have attached the things in the following way and I have purchased a new RFID Reader that works with the USB , the Relay is working good as well and everything is working Good , even the Push button to unlock the relay is working good as well but in short range like upto half meter long wire. But if i increase the wire long enough like 3 meters the switch automatically gets triggered even if it is not pushed. maybe because of the resistance or low voltage supplied by the Raspberry. i have already shared the code for the Raspberry in python above. @tlfong01
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(1) A new RFID Reader that works with the USB? Perhaps you should ask a new question. (2) Yes, 5V logic is less noisy. So perhaps try 5V logic. (3) Or try Dsub 9 pin double shield cable. (4) Or add decoupling caps 10uF, 0.1uF near button, and near Rpi GPIO. (5) Or use 20mA interface.– tlfong01Commented Jun 19, 2021 at 6:01
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1(4) Actually my old short answer Point 12 already gave details on how to avoid noise.– tlfong01Commented Jun 20, 2021 at 0:55
Question
The OP has a Rpi based electric door lock system which can be operated by either manual push button or RRFID card.
In normal operation the relay controls the electric lock power by 12VDC. When testing before 12V power in on, everything goes well: both push button and RFID card can activate and deactivate the 5V relay (hearing relay clicks).
However, when 12V lock power is switched on, only push button can activate and deactivate relay as before, this time also lock is activate and deactivate.
The big problem is this: RFID can perform the activate/deactivate only once. After the only one off operation, Rpi need to reset to do RFID operation again.
The OP wishes to know why the Rpi should be reset after every RFID operation, and of course how to avoid this silly unnecessarily Rpi resetting.
Update 2021apr25hkt2227
The OP confirms that even the 12V power is switched on before any test, the RFID's only one operation problem does not go away.
Answer
Short Answer
There are two types of electric lock: (a) NO (Normal Open), (b) NC (Normal Close). I am assuming the OP's lock is NC (Normal Close).
For NC lock, the +12VDC power wire goes to relay channel's COM terminal, and goes out at the NC terminal.
When 12V power is switched on, COM and NC is shorted. So +12VDC goes to the positive terminal of the lock. The negative terminal of the lock goes back to the Ground (0V) of the 12VDC power supply.
Now when the RFID reader reads a RFID card, Rpi will checks if RFID card read is valid, and if yes, would trigger the Relay channel. Now COM will disconnect from NC. In other words, the 12VDC power to the lock is cut off.
Now the fun starts at this point. The lock is actually a solenoid, which is an inductor. Now when the power to this inductor is cut off, the current flowing through the inductor path is cut off, and a back EMF voltage and resultant current would occur and flies back through a flyback diode, if there is one.
Either with or without a flyback diode, the back EMF will still trigger a spike voltage signal, and returns to the power ground.
If the 12V power supply ground line is physically connected for any length to the +5V logical power ground line of the Rpi, Rpi would experience a voltage spike and resets the RFID program running at Rpi.
So Rpi needs to be reset to restart the RFID program, and this is what annoyingly do after each RFID operation.
There are a couple of workarounds. The main idea is to decouple the 12V relay and lock power from to the 5V Rpi power.
If the OP is using a relay with a JD-Vcc jumper, he can do total optical isolation, as described in Appendix D.
The explanation of the JD-Vcc jumper operation is described in Ref 7.
There are other tricks to prevent relay/lock power from interfering the 5V Rpi logic power from the 12V relay/lock power. These trick include:
(a) Space power lines from logical/control lines
(b) Use two separate power supplies, one 5V (not stepped down from the 12V relay/lock power supply) Rpi, another 12V dedicated for relay/lock.
(c) Use bypass/decoupling capacitors 10uF and 0.1uF near to the power supplies. See Ref 8, Ref 9.
Long Answer
This is a troubleshooting question. I think we need to first study the Rpi python program to see how it works.
/ to continue, ...
References
(1) LXF230 RFID Controlled Magnetic Door Lock Introduction - lesp, GitHub
(2) 12VDC 60kG Electromagnetic door lock, - Kmoon, AliExpress, US$23
(3) RFID Lock Program Penzu Reading Log v0.1
(5) 5V Dual-Channel Relay Module (with optical coupler and JD-Vcc jumper) - Coimponents 101, 2021jan05
(6) 5V Dual-channel Relay Module (with optical coupler and JD-Vcc jumper) - OsoYoo 2017may27
(8) Clean Power for Every IC, Part 1: Understanding Bypass Capacitors - R Keim 2015sep21
(9) Clean Power for Every IC, Part 2: Choosing and Using Your Bypass Capacitors - R Keim 2015sep27
(11) (My rfid-rc522 reader stops reading after some time, how can I debug it? - EESE 2021apr28
(12) SDC Electromagnetic Door Lock Catalog - SDC
(13) SDC Excell Series Data Lock (250mA, 12VDC) - DSC
(15) Reducing sound noise when recording with Pi - Asked 1 year ago, Viewed 892 times
(16) Back EMF Suppression (For Magnetic Door Locks) - Progeny
(17) CY-180 12V 180kG Single Door Magnetic Door Lock - TaoBao ¥45
(18) How to use 12VDC Solenoid Door Lock - tlfong01 rpi.org.forum 2019jan13
(21) AliEx Magnetic Door Catalog
(21) Schotty Diode Selection Guide - 2019-Jan-17
(22) Back EMF Killed my PSU Postmortem 1/2
(23) Back EMF Killed my PSU Postmortem 2/2
(24) RFID reader (SimpleMFRC522, RC522, THM3060) and RF Power Meter - RpiSE, 2020apr21
(25) Door Controller Using JD-Vcc Relays - rpi.org/forum 2018jun21
(26) DC6V 1.5A 11.4mm 200g Electromagnetic Solenoid Door Lock - AliExpress US$14 (The OP's solenoid door dock)
(28) SPI-Py: Hardware SPI as a C Extension for Python
(31) LY-03 DC12V/24V Small Electromagnetic Drawer/Bolt Lock - AliExpress US$9
(33) Power MOSFET Driving Big Motor Problem - RpiSE Asked 2019feb09 Viewed 706 times
(34) How to measure inductance (of magnetic door lock) - Rose-Hulman Online 8,195 views
(35) Deedlock Electromagnetic Locks - Slimline Face to Face (Showing armature button)
Appendices
Appendix A - LX230 RFID Rpi python program listing
The main test program, without the RFID library, is only 80 something lines long. So it is worth our time studying carefully the complete listing.
(3) RFID Lock Program Study Notes v0.1 Penzu Link
LXF230-RFID-Door-Lock/SimpleMFRC522.py - lesp 2021apr25hkt2156
https://github.com/lesp/LXF230-RFID-Door-Lock/blob/master/SimpleMFRC522.py
import MFRC522
import RPi.GPIO as GPIO
class SimpleMFRC522:
READER = None;
KEY = [0xFF,0xFF,0xFF,0xFF,0xFF,0xFF]
BLOCK_ADDRS = [8, 9, 10]
def __init__(self):
self.READER = MFRC522.MFRC522()
def read(self):
id, text = self.read_no_block()
while not id:
id, text = self.read_no_block()
return id, text
def read_id(self):
id, text = self.read_no_block()
while not id:
id, text = self.read_no_block()
return id
def read_id_no_block(self):
id, text = self.read_no_block()
return id
def read_no_block(self):
(status, TagType) = self.READER.MFRC522_Request(self.READER.PICC_REQIDL)
if status != self.READER.MI_OK:
return None, None
(status, uid) = self.READER.MFRC522_Anticoll()
if status != self.READER.MI_OK:
return None, None
id = self.uid_to_num(uid)
self.READER.MFRC522_SelectTag(uid)
status = self.READER.MFRC522_Auth(self.READER.PICC_AUTHENT1A, 11, self.KEY, uid)
data = []
text_read = ''
if status == self.READER.MI_OK:
for block_num in self.BLOCK_ADDRS:
block = self.READER.MFRC522_Read(block_num)
if block:
data += block
if data:
text_read = ''.join(chr(i) for i in data)
self.READER.MFRC522_StopCrypto1()
return id, text_read
def write(self, text):
id, text_in = self.write_no_block(text)
while not id:
id, text_in = self.write_no_block(text)
return id, text_in
def write_no_block(self, text):
(status, TagType) = self.READER.MFRC522_Request(self.READER.PICC_REQIDL)
if status != self.READER.MI_OK:
return None, None
(status, uid) = self.READER.MFRC522_Anticoll()
if status != self.READER.MI_OK:
return None, None
id = self.uid_to_num(uid)
self.READER.MFRC522_SelectTag(uid)
status = self.READER.MFRC522_Auth(self.READER.PICC_AUTHENT1A, 11, self.KEY, uid)
self.READER.MFRC522_Read(11)
if status == self.READER.MI_OK:
data = bytearray()
data.extend(bytearray(text.ljust(len(self.BLOCK_ADDRS) * 16).encode('ascii')))
i = 0
for block_num in self.BLOCK_ADDRS:
self.READER.MFRC522_Write(block_num, data[(i*16):(i+1)*16])
i += 1
self.READER.MFRC522_StopCrypto1()
return id, text[0:(len(self.BLOCK_ADDRS) * 16)]
def uid_to_num(self, uid):
n = 0
for i in range(0, 5):
n = n * 256 + uid[i]
return n
Appendix C - Wiring Diagram
Appendix D - JD-Vcc Jumper Relay Wiring Diagram
Appendix E - Total optical isolation wiring diagram for the OP's application
Appendix F - Flyback Schottky Diode to protect PSU powering Magnetic Door
(21) Schotty Diode Selection Guide - 2019-Jan-17
(22) Back EMF Killed my PSU Postmortem 1/2
(23) Back EMF Killed my PSU Postmortem 2/2
Appendix G - N-channel Power MOSFET Controlled Magnetic Door Lock v0.3
Appendix H - YL-03 Solenoid Door Lock and IRL540N N-channel Power MOSFET V0.4
Appendix I - IRL540N Pinout
Appendix J - Wiring of Using N-channel Power MOSFET to switch on/off a 12V Solenoid/Marnetic Door Lock
/ to continue, ...
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1If we turn it on before then it’s still the same issue , it’ll scan the RFID card once only and later on it’ll not scan the RFID. The RFID and coding is okay and is not having any issue with anything. Like I explained it works perfect with the relay but as soon as the current is passed from the relay things are changed. So there must be something related to hardware and the relay that I am missing. Commented Apr 25, 2021 at 14:07
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Thank you for your confirmation and clarification. (1) I agree that the python program has not problem. I skimmed it once and concluded that it should be written by an expert. I just want to get a rough idea of how the main program works, and see if I insert any debugging statement somewhere. (2) I also agree that we (you!) might be doing something silly. or doing something we should not do and we don't know that. (3) I now guess this might be a tricky problem, so I it might take us sometime before an eureka. :)– tlfong01Commented Apr 25, 2021 at 14:24
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Just to make sure: (1) Your relay wiring seems a bit weird to me. Usually the +12V line should go to the COM terminal, and go out at the NO (Normally Open) terminal. But you go out at the NC (Normally Connect). (2) Do you have any wiring diagram, or schematic to check out? SORRY - Ignore my question. I found the wiring diagram in the doc.– tlfong01Commented Apr 25, 2021 at 14:39
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1Sure i am waiting , Just FYI i have tried both the high level and low level relay but all of them behaved the same . It Scanned for the first time and then nothing for the second time. Commented Apr 27, 2021 at 6:05
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1@tlfont01 I need to ask one more thing, I have fixed everything and it is working all good, i have changed some of the hardware and some part of the code and developed a new hardware running on the doors from last 15 days , now the issue here is the Button , unfortunately the wire of one of the button is more then 3 meters and i am using ` from gpiozero import Button, OutputDevice release = Button(27)` for the button but due to the long wire it is automatically getting triggered. I will share the code in the next line. Commented Jun 17, 2021 at 11:01