I am using python, and I am getting an error where it says "GPIO.output(24, False)" in the else statement. I don't know what it means, or how I fix it.

from picamera import PiCamera
from time import sleep
import RPi.GPIO as GPIO
import time

GPIO.setup(23, GPIO.IN, pull_up_down=GPIO.PUD_UP)#Button to GPIO23
camera = PiCamera()

    while True:
        button_state = GPIO.input(23)
        if button_state == False:
            GPIO.output(24, True)
            print('Button Pressed...')
            GPIO.output(24, False)

except KeyboardInterrupt:
  • 1
    Python gives clear error messages. This appears to be a Python question, i.e. not Pi specific, so off-topic.
    – joan
    Jun 8, 2022 at 21:15
  • reduce your code to only print a message when the button is pressed ... camera and button are not related, they are two completely separate devices
    – jsotola
    Jun 9, 2022 at 1:26

1 Answer 1


You need to setup GPIO24 as output at the start of your code:

GPIO.setup(24, GPIO.OUT)
  • The error has gone away, but the camera still doesn't preview when I press the button. That might be a problem with some of the other code though. Thanks
    – Jase Anger
    Jun 8, 2022 at 21:25
  • Now it is saying "This channel is already in use, continuing anyway. Use GPIO.setwarnings(False) to disable warnings. GPIO.setup(24, GPIO.OUT)" Nothing is plugged into GPIO 24 though. –
    – Jase Anger
    Jun 8, 2022 at 21:40
  • Don't worry about the warning. Does your camera actually work if you just use 'from picamera import PiCamera,from time import sleep, camera = PiCamera(), camera.start_preview(),sleep(10)' ?
    – CoderMike
    Jun 8, 2022 at 21:43
  • Yes it does when I do something simple like that.
    – Jase Anger
    Jun 8, 2022 at 21:47
  • Amend your question with your new code and add print(button_state) after you set it. Does the output change when you press your button?
    – CoderMike
    Jun 8, 2022 at 21:50

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