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I am working with GPIO where I want to read a vacuum sensor's output voltage. Using a voltmeter from the output to the pi's ground, I measured the voltages.

  • ON State: 21V
  • OFF State: 15V I know that GPIO is designed to only receive 3.3v for input. How can I wire the pi so that it can receive the vacuum sensor's output without damaging the pi?

Here is a related link that I looked at: Connecting 15V to GPIO w/o dividing voltage

If there are any components that I have to purchase to make this work, please let me know.

Thank You!

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  • Might be easiest to use a voltage divider to reduce the voltage and a ADC chip to read the analogue voltage.
    – CoderMike
    Jul 30 at 19:18
  • what is preventing you from supplying the vacuum sensor with lower voltage?
    – jsotola
    Jul 30 at 19:47
  • jsotola, The vacuum switch is rated 10.8 to 30 VCC. We are currently supplying it 24V. We could supply it less voltage, but it would still be over 3.3V.
    – Danny
    Jul 30 at 22:54
  • This is not a Pi question but about designing a circuit to connect to an unspecified source. If the device ACTUALLY returns those voltages it would difficult to detect the 7:5 change in value without some external electronics. I expect the voltages you measure are an artefact of the circuit and would vary with loading.
    – Milliways
    Jul 31 at 4:02

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The pi is very sensitive when it comes to the tension on the GPIO. When you are working with higher tensions, be very careful.

I would use an opto-coupler to protect my Pi.

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Your zener would be somewhere above 15V. The resistor on the led-side of the opto-coupler depends on the zener value and the opto-coupler that is used..

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