I know that my USB powered Hard Drive doesn't work, but what is the minimum power requirement that the Raspberry Pi can fulfil for devices that connect via USB?
Please note that this answer was written in June, 2012, and has not been revised since the day after it was submitted. Therefore:
1. The Raspberry Pi model to which this Q & A refer is the first generation Model B (maybe Model A).
2. The answer given here (100mA) is incorrect for later models of the Raspberry Pi.
END of NOTE
You should not draw more than about 100mA from the USB ports.
In reality, it is more complicated than this.
I've taken two screenshots from the Device B schematic (released here):
Power in (fig A):
We can see that the 5 volt line (+5V0) is powered directly from the USB input power, through a 1.1A, 6V Polyfuse (miniSMD). I believe this means that the 5V input is current limited to 1.1A (maximum hold current, not peak).
Let's assume that you're powering the device from a regulated 5V supply capable of supplying at least 700mA.
USB Power out (fig B):
As we can see from fig B, the USB ports are current-limited by polyfuses (miniSMDC014) to 140mA (constant draw).
Some users have discovered that their polyfuses at 100mA have approx 5 Ohm resistance, causing a voltage drop of V = iR = 0.1*5 = 0.5 V. This isn't ideal, as this means the output USB voltage would be 5 - 0.5 = 4.5 V. (This may cause some devices to not function if they expect 5.0 V)
As the current draw on the USB increases (ie to 150mA), voltage drops further - 0.15*5 = 0.75 V, resulting in an output voltage of 5 - 0.75 = 4.25 V, which is below the USB spec minimum voltage of 4.40V (source). This is assuming the resistance doesn't increase with current draw, although in reality the resistance/current draw plot will look something like this:
From a Q/A with Pete Lomas:
The fuses kick in hard around 280mA and fold back and limit to 140mA. If you remove them then all you have for protection is the 700mA inbound fuse. The tracking on the board is good for 500mA+ so you could if you really wanted to. What about a powered hub – to power the Pi and bigger USB devices.
To power higher power devices: (i.e. USB 2 devices)
You should use a powered USB hub, that can supply >= 0.5A per USB port. This means if your USB hub has 4 ports, it should use at least a 2A power supply.
If you don't want to use a USB hub with a second power supply, you can do one of the following options:
These methods are not recommended, and may damage your board/devices.
- Create/buy a split USB cable that uses a separate 5V source (such as your input source).
Raspi USB out (pins TX, RX, GND) ___ \_____ device 5V supply (pins 5V, GND) ___/
- Join the output of the two polyfuses (solder a jumper across). As the polyfuse current is being split, this will allow up to ~200mA for one USB device, or 50/150 across two.
You could also join the VCC of both USB ports: (untested)
- Connect the input VCC to the output VCC (disconnect the polyfuses first?). This will allow you to draw as much (combined) as your input can supply.
Disclaimer: I am not involved in the design of the Raspberry Pi, and am not an expert on polyfuses. Modifying your Raspberry Pi is not recommended, will void your warranty, and may damage things. Please do not sue me.
Please feel free to correct any mistakes I have (probably) made!
Just noting that the rev 2.0 board no longer has the USB polyfuses, just the input 1.1A polyfuse. So the issues mentioned here should no longer be present in current generation Raspberry Pi boards.