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I've been getting into GPIO recently with the GPIOZero library but when i first tried it today it completely failed. As my first foray into GPIO i set up a circuit to light up an LED with the push of a button, so simple nothing could go wrong, right? I imported the library like so: from gpiozero import Button, LED then i set up my components: led = LED(17) then the button: btn = Button(4) And then this happened:

enter image description here

I have attempted to re download the library but sudo apt-get install python3-gpiozero said that it was the latest version.

This is the circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

First: what doe this error mean?

Second: How can i fix it?

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  • It may be a bug. Try using sudo python to see if you still get the same error message.
    – joan
    Jun 3, 2016 at 14:39
  • @joan if i run sudo python3 and then enter in the python commands i get the error but if i save i file with the code it does nothing
    – sir_ian
    Jun 3, 2016 at 15:07
  • The script works for me (with or without sudo). I'd guess you have an inconsistent version of the RPi.GPIO module.
    – joan
    Jun 3, 2016 at 15:57
  • @joan finally got around to experimenting with this some more and it does work with pins 27 and 17 and probably more more but just not with pin number @#%$^&$ 4
    – sir_ian
    Jun 22, 2016 at 18:23

1 Answer 1

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I have seen this before, when the 1-wire interface has been enabled. If you've enabled 1-wire in Raspberry Pi configuration, you won't be able to use GPIO4 for general use. Try disabling it:

https://github.com/bennuttall/one-wire-temperature-sensor

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  • Sadly this pi is no longer in service so I can't test it.
    – sir_ian
    Nov 25, 2016 at 21:33

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