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I am a beginner in physical computing and accidentally gave my Pi 5volts and my Rasbperry Pi shut down (I'm really worried it's becoming more damaged overtime if I keep on doing this), because I was using a module sensor meant for arduino that delivers 5 volts as an input. I'm trying to use a voltage divider so that only 3 volts will enter one of the Pi's GPIO pins. I understand the schematics and the drawing, but I'm having a hard time picturing what this looks like on a breadboard. Could someone please send me pic of what a voltage divider looks like? I would appreciate that! Also, just to be clear, IS it okay to ground 5V into a ground pin in the Raspberry Pi or will this cause it to be damaged as well? The sensor has a Vcc, Grnd, AO (analogue input), and DO input as its integrated pins. For reasons I won't disclose, I won't be able to acquire a ADC converter, and plus I don't need to detect any kind of "real world values" just the instance when the sensor immediately detects something its supposed to detect. Also I am only able to use a 10K and 330 ohms resistor....

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    Here is a breadboard layout example of a voltage divider to drop the 5v output from the Echo pin to the Pi GPIO pin to 3.3v. – stevieb Mar 3 '17 at 14:59
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If you're supplying voltage via GPIO, be careful. There is no voltage regulation performed on the GPIO pins. This article indicates:

"If an incorrect voltage is applied, or a current spike occurs on the line you can permanently damage your Raspberry Pi. At best, you’ll “burn out” some or all of the GPIO pins, at worst you can fry your Pi! So be careful."

  • Wow. Downvotes without an explanation? Did I miss something from the OP's question? – Dan Esparza Mar 4 '17 at 18:47

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