1

So, I am trying to use my RPi model 2B to control a DC motor with an l293d controller. I have moved onto the python3 script and imported the 'l293d' module. Here is my code...

import l293d.driver as l293d
motor1 = l293d.motor(22,18,16)
for i in range(200):
    motor1.clockwise()
l293d.cleanup()

and the error that it returns is...

AttributeError: module 'l293.driver' has no attribute 'motor'

Can someone please explain why this error is occurring. Thanks.

| improve this question | |
  • Not Pi specific. The message is quite explicit. module 'l293.driver' has no attribute 'motor'. That means there is nothing called motor in the module l293d.driver (whatever that is). – joan Aug 6 '18 at 20:51
  • Did you create a file named l283d.py yourself? That would confuse Python – Dirk Aug 6 '18 at 20:59
  • No, the file is called 'motor.py', but it is in python3. Is this a module for python2 only? – jdw136 Aug 6 '18 at 21:01
3

If you read the documentation, there are two mistakes in your code. First, just use import l293d. Second, use motor1 = l293d.DC(22, 18, 16)

There isn't a motor attribute, but there is a DC attribute for DC motors.

This runs on my system.

jay@gotham:~/python$ python3 test.py
[l293d]: Can't import RPi.GPIO; test mode has been enabled:
http://l293d.rtfd.io/en/latest/user-guide/configuration/#test-mode
[l293d]: spinning clockwise motor at BOARD pins [22, 18 and 16]
[l293d]: spinning clockwise motor at BOARD pins [22, 18 and 16]

(... Many repetitions of the above line removed ...)

[l293d]: Cleanup not needed when test_mode is enabled.
jay@gotham:~/python$
| improve this answer | |
2

According to documentation page for the l293d Python library, you've used syntax that's incorrect. The docs suggest this may work: 

import l293d  
motor1 = l293d.DC(22, 18, 16)

then the rest of your code.

| improve this answer | |
  • @NomadMaker called out a mistake in my answer; +1 for him :) I'm going to edit my answer just to eliminate a potential source of confusion. – Seamus Aug 7 '18 at 1:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.