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We are trying to use zmqsend (it's part of the ffmpeg repository) to communicate with a ffmpeg instance. On Raspbian, ffmpeg is configured with --enable-libzmq, and libzmq-dev is installed, but zmqsend is not found. How to get it, besides by rebuilding ffmpeg?

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  • ffmpeg documentation states Look at tools/zmqsend for an example of a zmq client which can be used to send commands processed by these filters - it's an example - you have to compile it yourself, you dont' need to compile all of ffmpeg yourself to compile that example code
    – Jaromanda X
    Commented Feb 2, 2019 at 23:13
  • @JaromandaX We've tried that, you do need all of ffmpeg. Trying to compile it by itself gives gazillions of linker errors.
    – whoKnows
    Commented Feb 3, 2019 at 0:53
  • if you install the appropriate dev packages then you dont' need to compile ffmpeg
    – Jaromanda X
    Commented Feb 3, 2019 at 1:54
  • @JaromandaX Which dev packages, exactly?
    – whoKnows
    Commented Feb 3, 2019 at 21:09
  • i.e. since zmqsend refers to libavutil, start with libavutil-dev
    – Jaromanda X
    Commented Feb 3, 2019 at 22:15

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Zmqsend can indeed be compiled independently. You need libzmq3-dev (not libzmq-dev) and libavutil-dev. 

cd FFmpeg/
./configure
cd tools/
gcc -o /where/you/want/zmqsend zmqsend.c -I.. `pkg-config --libs --cflags libzmq libavutil`
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  • Please accept your own answer with a click on the tick on its left side. Only this will finish the question and it will not pop up again year for year.
    – Ingo
    Commented Mar 3, 2020 at 20:32

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